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Devante runs a 100-meter race. 5 seconds after the race started Devante is 35 meters from the starting line and reaches his max speed; he runs at this max speed for the rest of the race. Devante notices that he is 71 meters from the starting line 9 seconds after the race started. What is Devante's max speed? meters per second Preview Suppose Devante runs for an additional z z seconds after reaching his max speed... How far will Devante travel during those additional z z seconds? meters Preview What is Devante's distance from the starting line 5 + z 5+z seconds after the race started? meters Preview What is Devante's distance from the starting line x x seconds after the race started (provided x ≥ 5 x≥5)?

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umairfeb221999

Answer:

a) The max speed of Devante is 9 meter per second.

b) Devante travel  [tex](z\ z*9 \ meter/sec)[/tex] for additional [tex]zz \ seconds[/tex].

c) Devante's distance from stating line 5+z seconds after the race started is [tex]35\ meters+z*9\ meter / sec[/tex].

d) Devante's distance from starting line x x seconds after the race started is [tex]35\ meters+(x \ x-5)*9\ meter/sec[/tex], Provided [tex]x\geq 5[/tex].

Step-by-step explanation:

a) Devante reaches 35 meter away from starting line in 5 seconds and after 9 secs he realizes he is 71 meter away from starting line.

So,

           [tex]Distance=71-35=36\ meters[/tex]

            [tex]Time=9-5=4\ seconds[/tex]

Then,

    [tex]Max \ speed \ of \ Devante =36/4=9\ meter/second[/tex]

b) Devante run additionally for z z seconds after reaching his max speed.

So,

            [tex]Distance\ covered\ additionally=z\ z*9\ meter/second[/tex]

c) Devante's distance from starting line 5+z seconds after..

        [tex]Distance\ covered\ initially\ in\ 5\ seconds=35\ meters[/tex]

So,

        [tex]Total\ distance=35\ meters+((5+z)-5)*9\ meter/sec[/tex]

                                [tex]=35\ meters+(z)*9\ meter/sec[/tex]

d) [tex]Initial\ distance=35\ meters[/tex]

   [tex]Remaing\ seconds\ after\ reaching\ 35\ meters=x\ x-5\ sec[/tex]

So, provided   [tex]x\geq 5[/tex].

    [tex]Devante's\ distance\ from\ starting\ line =35\ meters+(x\ x-5\ sec)*9\ meter/sec[/tex]