Respuesta :
Answer:
s = 27 m
Explanation:
given,
acceleration of the car, a = 6 m/s²
time of the travel, t = 3 s
final speed of the car, v = 0 m/s
using equation of motion
v = u + a t
0 = u - 6 x 3
u = 18 m/s
initial speed of the car = 18 m/s
Again using equation of motion
v² = u² + 2 a s
0 = 18² - 2 x 6 x s
12 s = 324
s = 27 m
Distance travel by the car is equal to 27 m.
Answer:
Explanation:
Given
car starts from rest i.e. initial velocity is zero [tex](u=0)[/tex]
acceleration [tex]a=6\ m\s^2[/tex]
Time take [tex]t=3\ s[/tex]
using
[tex]x=ut+\frac{1}{2}at^2[/tex]
where
x=displacement
u=initial velocity
a=acceleration
t=time
so car travels 27 m in first 3 second
