Answer:
a) 23.551 hp
b) 516.89 hp
Explanation:
given:
[tex]F_{d} =\frac{1}{2} C_{d} A_{p} V^{2} \\V_{a}=25 m/hr-->25*\frac{5280}{3600} =36.67ft/s\\V_{b}=70 m/hr-->70*\frac{5280}{3600} =102.67ft/s\\\\C_{d}=.28\\A=25 ft^2\\p=.075lb/ft^2[/tex]
required:
the power in hp
solution:
[tex](F_{d})_{a} =\frac{1}{2} C_{d} A_{p} V_{a} ^{2}[/tex].............(1)
by substituting in the equation (1)
=353.27 lbf
[tex](F_{d})_{b} =\frac{1}{2} C_{d} A_{p} V_{b} ^{2}[/tex]..........(2)
by substituting in the equation (2)
= 2769.29 lbf
power is defined by
P=F.V
[tex]P_{a}=[/tex]353.27*36.67
=12954.411 lbf.ft/s
=12954.411*.001818
=23.551 hp
[tex]P_{a}=[/tex]2769.29*102.67
= 284323 lbf.ft/s
= 284323*.001818
= 516.89 hp
