Explanation:
The given data is as follows.
mass = 227.8 kg, volume = 0.1189 [tex]m^{3}[/tex]
It is known that formula for volume of a sphere is [tex]\frac{4}{3} \pi r^{3}[/tex] and density is as follows.
Density = [tex]\frac{mass}{volume}[/tex] ........ (1)
= [tex]\frac{227.8 kg}{0.1189 m^{3}}[/tex]
= 1915.895 [tex]kg/m^{3}[/tex]
Hence, putting the given values into equation (1) as follows.
Density = [tex]\frac{mass}{volume}[/tex]
1915.895 [tex]kg/m^{3}[/tex] = [tex]\frac{227.8 kg}{\frac{4}{3} \pi r^{3}}[/tex]
[tex]8021.213 r^{3}[/tex] = 227.8
r = 0.305 [tex]m^{3}[/tex]
Thus, we can conclude that radius of the sphere is 0.305 [tex]m^{3}[/tex].
