Answer:
After 120.0 minutes the the concentration of reactant A will be 0.175 M
Explanation:
Rate constant of the reaction = k =[tex]0.03 M^{-1} min^{-1}[/tex]
From the units of rate constant is very much obvious that reaction of second order kinetics.
Initial concentration of reactant = [tex][A_o]=0.50M[/tex]
Final concentration of A after time t = [tex][A]=0.175 M[/tex]
t = ?
Integrated rate law for second order kinetics is given by:
[tex]\frac{1}{[A]}=kt+\frac{1}{[A_0]}[/tex]
[tex]\frac{1}{0.175 M}=0.031 M^{-1} min^{-1}\times t+\frac{1}{0.500 M}[/tex]
t = 119.8 min ≈ 120.0 min
After 120.0 minutes the the concentration of reactant A will be 0.175 M
