Respuesta :
Answer:
Bowl A: 11/48 pounds of chili
Bowl B: 11/24 pounds of chili
Bowl C: 33/48 pounds of chili
Step-by-step explanation:
Since the amount of chili, Karyn has to put in any of the three bowls doesn’t have to be same.
Let’s assume the following share for each bowl:
1 part of the 11/8 pounds for bowl A
2 parts of the 11/8 pounds for bowl B
3 parts of the 11/8 pounds for bowl C
Adding parts together gives 1+2+3=6 parts of the total 11/8 pounds of chili
Bowl A: 1/6 * (11/8) = 11/48 pounds of chili
Bowl B: 2/6 * (11/8) = 11/24 pounds of chili
Bowl C: 3/6 * (11/8) = 33/48 pounds of chili
The amount of chili in the first bowl is 11/48, in the second bowl is 11/24 and in the third bowl is 33/48.
Given that
Karyn has 11/8 pounds of chili to put into three bowls.
The amount of chili in each bowl does not have to be the same.
We have to determine
How much chili could Karyn put into each bowl?
According to the question
Karyn has 11/8 pounds of chili to put into three bowls.
The amount of chili in each bowl does not have to be the same.
Let the amount of chili in the first bowl be x/6.
The amount of chili in the second bowl be x/6.
The amount of chili in the third bowl be x/6.
Therefore,
The amount of chili in the first bowl is,
[tex]= \dfrac{11}{8} \times \dfrac{1}{6}\\ \\ = \dfrac{11}{48}[/tex]
The amount of chili in the second bowl is,
[tex]= \dfrac{11}{8} \times \dfrac{2}{6}\\ \\ = \dfrac{22}{48}\\ \\ = \dfrac{11}{24}[/tex]
The amount of chili in the third bowl is,
[tex]= \dfrac{11}{8} \times \dfrac{3}{6}\\ \\ = \dfrac{33}{48}[/tex]
Hence, the amount of chili in the first bowl is 11/48, in the second bowl is 11/24 and in the third bowl is 33/48.
To know more about Equation click the link given below.
https://brainly.com/question/11612856
