In Andalusian fowls,black individuals (B) and white individuals (W) are homozygous.A homozygous blackboard is crossed with a homozygous white bird.The offspring are all bluish gray. Show the cross as well as the genotype and phenotype of the parents and offspring.

The phenotype of the parents is: black for the homozygous black bird and white for the homozygous white bird. The phenotype of all the offsprings is bluish gray

Explanation: From the information provided, black trait B and white trait W are homozygous therefore the genotype of the parent are BB and WW for the black and white bird respectively. Their phenotype is black because the black trait B is dominant and white because the white trait W is also dominant.

See the attached punnet for the cross between the two birds.

throwdolbeau throwdolbeau · Answer 2 · 2022-02-04T12:43:14+01:00

The genotype of the parents are BB and WW while the genotype is BW.

Given:

The phenotype of the parents is: black for the black bird and white for the white bird.
The phenotype of all the formed organism is bluish gray.

The trait that first appears or is visibly expressed in the organism is called the dominant trait.

The trait that is present at the gene level but is masked and does not show itself in the organism is called the recessive trait.

Their phenotype is black because the black trait B is dominant and white because the white trait W is also dominant.

Find more information about "phenotype" here:

brainly.com/question/16616523