Answer: 55 residues
Step-by-step explanation:
We are given that length of sheet= 193 Å
We need to find out the number of residues in this segment.
Now in an anti parallel β sheet, the repeat comes out after every 7Å.
In every repeat, there are 2 residues.
So, to find out the number of residues in segment, we multiply the number of segments with the residues in every segment.
Residues in segment= [tex]\frac{193}{7}*2\\[/tex]
Residues in segment= 55.14
Or 55 residues.
The number of residues in the given segment is; 55 residues
We are given;
length of sheet; L = 193 Å
We know that in an anti parallel β sheet, the repeat usually comes out after every 7Å. This means that for every repeat, we will have 2 residues.
Thus, the number of residues in the segment is;
Residues in segment = (193/7) * 2
Residues in segment = 55.14
Approximating to a whole number gives 55 residues
Read more about Beta sheets at; https://brainly.com/question/19955121
