The equation that matches the given table is
y = 10x + 40
Solution:
General equation of a line : y = mx + c
Let us find the equation of the table.
Common differences of X:
0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1
Common differences of Y:
50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10
[tex]$m=\frac{\Delta y}{\Delta x}[/tex]
[tex]$m=\frac{10}{1}[/tex]
m = 10
Substitute m = 10 in general equation of a line
y = 10x + c
To find the constant term, substitute x = 0 and y = 40.
40 = 10(0) + c
40 = 0 + c
40 = c
c = 40
Therefore the equation of a line is y = 10x + 40.
Hence the equation that matches the given table is y = 10x + 40.
