Respuesta :
Answer:
1. [tex]d*1.49[/tex]
2. [tex]d/0.67[/tex]
Step-by-step explanation:
One equation is already given in the statement which can give the result.
Lets assume the area of painting = d = 10 sq inch
Now following expressions will give the same answer.
1. [tex]d+0.49d=10+(0.49*10)=14.9 sq inch[/tex]
2. Multiplying the percentage d, As the area increases by 49 % which means that D is multiplied by increased amount of 49%
equation will be
[tex]d*1.49=10*1.49=14.9sqinch[/tex]
3. Calculating the percentage increment = 1/1.49=0.67
Now dividing this value with d will give the same area.
[tex]=d/(1/1.49)=10/0.67=14.9 sq inch[/tex]
Expressions for the area of the enlarged painting,
1). Area = d + 0.49d
2). Area = 1.49d
3). Area = [tex]\frac{d}{0.67114}[/tex]
Given in the question,
"An art teacher enlarged the area of a painting by 49%"
1). Let d = Area of the original painting
Increase in the area = 49%
Therefore, expression representing the area of new painting will be,
Area = d + 0.49d
2). If the original area of the painting is increased by 49%,
Factor to be multiplied to the original area = 1.49
Therefore, expression for the new area will be,
Area = 1.49d
3). Since, 1.49d can be written as [tex]\frac{d}{\frac{1}{1.49} }[/tex].
Value of [tex]\frac{1}{1.49}=0.67114[/tex]
Therefore, expression for the area will be,
Area = [tex]\frac{d}{0.67114}[/tex]
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