When the solution to x2 − 11x + 5 is expressed as 11 plus or minus the square root of r, all over 2, what is the value of r? x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a
A.2
B.5
C.101
D.141

Quadratic equations are second-degree algebraic expressions and are of the form ax² + bx + c = 0, Where a and b are the coefficients, x is the variable, and c is the constant term.

The roots of the quadratic equation can be written as (x ± r) or

[-b±(√b² - 4ac)]/2a

Given equation is x² − 11x + 5 where a=1, b=-11, c=5 and is expressed as(11 ± √r)/2

roots of the equation through formula [-b±(√b² - 4ac)]/2a is

[-( -11 ) ± ( √121 - (4 × 1 × 5 ) ) ] / (2 × 1)

roots are 10.52 , 0.4751

equate (11 ± √r)/2 with 10.52 , 0.4751

(11 + √r)/2 = 10.52 (11 - √r)/2= 0.4751

(11 + √r) = 21.04 (11 - √r)= 0.9502

r=100.8 r= 100.998

Thus the value of r is roughly 101

The correct option is "c'

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When the solution to x2 − 11x + 5 is expressed as 11 plus or minus the square root of r, all over 2, what is the value of r? x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a A.2 B.5 C.101 D.141

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When the solution to x2 − 11x + 5 is expressed as 11 plus or minus the square root of r, all over 2, what is the value of r? x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a
A.2
B.5
C.101
D.141