Answer:
[tex]8\pi \ in^2[/tex]
Step-by-step explanation:
1. Find the area of the circle with diameter of 2 in. If diameter is 2 in, then the radius is [tex]2\div 2=1\ in.[/tex]
Area [tex]=\pi r^2=\pi\cdot 1^2=\pi \ in^2[/tex]
2. Find the area of the circle with diameter of 6 in. If diameter is 6 in, then the radius is [tex]6\div 2=3\ in.[/tex]
Area [tex]=\pi r^2=\pi\cdot 3^2=9\pi \ in^2[/tex]
3. Find the difference in area:
[tex]9\pi -\pi =8\pi \ in^2[/tex]
