Answer: The amount remained after 151 seconds are 0.041 moles
Explanation:
All the radioactive reactions follows first order kinetics.
Rate law expression for first order kinetics is given by the equation:
[tex]k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}[/tex]
where,
k = rate constant = [tex]4.82\times 10^{-3}s^{-1}[/tex]
t = time taken for decay process = 151 sec
[tex][A_o][/tex] = initial amount of the reactant = 0.085 moles
[A] = amount left after decay process = ?
Putting values in above equation, we get:
[tex]4.82\times 10^{-3}=\frac{2.303}{151}\log\frac{0.085}{[A]}[/tex]
[tex][A]=0.041moles[/tex]
Hence, the amount remained after 151 seconds are 0.041 moles
