If the interplanar distance in the crystal is 287 pmpm , and the angle of maximum reflection is found to be 7.28 ∘∘, what is the wavelength of the x-ray beam? (Assume n=1n=1.)

Respuesta :

Answer: The wavelength of X-ray is [tex]7.27\times 10^{-11}m[/tex]

Explanation:

To calculate the wavelength of the radiation, we use the equation given by Bragg, which is:

[tex]n\lambda =2d\sin \theta[/tex]

where,  

n = order of diffraction = 1

[tex]\lambda[/tex] = wavelength of the X-ray = ?

d = spacing between the crystal planes = [tex]287pm=2.87\times 10^{-10}[/tex]      (Conversion factor:  [tex]1m=10^{12}pm[/tex] )

[tex]\theta[/tex] = angle of diffraction = 7.28°

Putting values in above equation, we get:

[tex]1\times \lambda=2\times 2.87\times 10^{-10}\times \sin (7.28)\\\\\lambda=\frac{2\times 2.87\times 10^{-10}\sin (7.28)}{1}\\\\\lambda=7.27\times 10^{-11}m[/tex]

Hence, the wavelength of X-ray is [tex]7.27\times 10^{-11}m[/tex]