Roulette: A Nevada roulette wheel has 38 pockets. Eighteen of them are red, eighteen are black, and two are green. Each time the wheel is spun, a ball lands in one of the pockets, and each pocket is equally likely. Part: 0 / 20 of 2 Parts Complete Part 1 of 2
(a) What is the probability that the ball lands in a red pocket
(b) If you bet on red on every spin of the wheel,you will lose more than half the time in the long run.Explin why this is so.

Respuesta :

Answer:

a.) 9/19

Step-by-step explanation:

Total number of pockets = 38.

Number of red pockets = 18

Number of Black pockets = 18

Number of green pockets = 2

a.) Probability of landing in a red pocket = 18/38 = 9/19.

b.)Since the number of red pockets is not up to half of the number of total pockets, that means if you bet on the red with every spin, you will definitely not win up to to half the times, that explains why you will lose more than half the number of times you bet on the red for each spin.

Probability of an event is the measurement of its chance of occurrence. The needed probability along with reason for more lose is:

  • The probability that the ball lands in a red pocket is 0.46 approx .
  • The reason of loosing more than half the time in long run if betting on red on every single spin is because the probability of not getting red is more than getting red.

How to calculate the probability of an event?

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}[/tex]

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

Since each of the pocket is equally likely, and there are total 38 pockets, so n(S) = 38

From the figures given in the problem, we get:

  • n(Getting Red) = 18
  • n(Getting black) = 18
  • n(Getting green) = 2

Therefore, we get the probability of getting red color when ball lands on a pocket of the considered roulette wheel as:

P(Getting red ) = n(Getting red)/n(S) = [tex]\dfrac{18}{38} \approx 0.46[/tex]

P(Not getting red) = 1 - P(Getting red) [tex]\approx 0.54[/tex]

The probability of not getting red is 0.54, and the probability of getting red is 0.46.

Since in the long run, the count of wins would follow the probabilities more and more, therefore, if we bet on red colored pocket again and again, as the ball is more probable to not come on red pockets, so we will lose more.

Therefore, the needed probability along with reason for more lose is:

  • The probability that the ball lands in a red pocket is 0.46 approx.
  • The reason of loosing more than half the time in long run if betting on red on every single spin is because the probability of not getting red is more than getting red.

Learn more about probability here:

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