Answer:
It is required 0.2289 moles of H₂ and it's been produced 0.1526 moles of NH₃
Explanation:
Reaction is: N₂(g) + 3H₂(g) → 2NH₃(g)
Ratio in the reactants is 1:3
So 1 mol of nitrogen needs 3 moles of hydrogen for the reaction
0.0763 moles may need (0.0763 . 3)/1 = 0.2289 moles of H₂
In the reaction ratio is 1:2, or 3:2. It is the same if we use the nitrogen or the hydrogen.
1 mol of N₂ produces 2 moles of ammonia
0.0763 mol of N₂ will produce 0.1526 moles of ammonia
3 moles of H₂ produce 2 moles of amonia
0.2289 moles of H₂ may produce (0.2289 . 2)/3 = 0.1526 moles of NH₃
0.0763 moles of nitrogen will react with 0.2289 moles of hydrogen to form 0.1526 moles of ammonia.
The balanced chemical reaction has been able to find the number of moles of reactant and product.
The given balanced equation will be:
[tex]\rm N_2\;+\;3\;H_2\;\rightarrow\;2\;NH_3[/tex]
From the equation, 1 mole of nitrogen reacts with 3 moles of hydrogen to form 2 moles of ammonia is formed.
0.0763 moles of Nitrogen = 0.0763 [tex]\times[/tex] 3 moles of Hydrogen
0.0763 moles of nitrogen = 0.2289 moles of Hydrogen
Thus, for 0.0763 moles of Nitrogen, 0.2289 moles of Hydrogen is required to form ammonia.
From the balanced chemical equation,
0.0763 moles of Nitrogen = 0.0763 [tex]\times[/tex] 2 moles of Ammonia
0.0763 moles of Nitrogen = 0.1526 moles of ammonia.
Thus, 0.0763 moles of nitrogen will form 0.1526 moles of ammonia.
For more information about the number of moles, refer to the link:
https://brainly.com/question/14919968
