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How many milliliters of 0.121 M HCl are needed to neutralize 44.3 mL 0.274 M Ba(OH)2? Write the equation and don't forget to balance it! Report your answer to the tenths place. Do not include units.

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Answer:

100 mL is the volume of HCl needed to neutralize the 44.3 of Ba(OH)₂

Explanation:

This is the chemical equation:

2HCl + Ba(OH)₂  →  BaCl₂ + 2H₂O

Formula for neutralization is:

Molarity of acid . Volume of acid = Molarity of base . Volume of base

0.121 . Volume of acid = 0.274 . 44.3

Volume of acid = (0.274 . 44.3) / 0.121 → 100

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