contestada

Two masses, m = 3.31 kg and m = 7.29 kg, are connect by a string of negligible mass. The string passes over a frictionless pulley so that m and m hang down on opposite sides of the pulley. The whole system is released from rest. Calculate the tension in the string as the masses are moving.

Respuesta :

Answer:

66.2N

Explanation:

form two equations and solved them simultaneously

sidhu36

Explanation:

The equation of motion for mass M1 :  M1a=T−M1g ...(1)

and for mass M2 : M2a=M2g−T ....(2)

(1)+(2)⇒a(M1+M2)=(M2−M1)g

or a=M1+M2(M2−M1)g=7+12(12−7)(10)=(50/19)m/s2

From (1), T=M1(a+g)=7(50/19+10)=88.42N

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