Respuesta :
Answer:
The partition of either homologous chromosomes or sister chromatids during the anaphase of meiosis I or meiosis II separately is called non brokenness.
The right answer is alternative D i,e non disjunction of X chromosomes during meiosis II.
At the point when nondisjunction happens during anaphase II ( meiosis II ) , that outcomes in any event one sets of sister chromatids not isolating and remaining together. In such cases, two cells will have the ordinary haploid chromosomes number. Be that as it may, one cell will have an additional chromosome (n + 1) and one will be feeling the loss of a chromosome (n - 1).
In the event that we just think about XY chromosomes, as meiosis I is ordinary so homologous chromosomes will isolate. One cell will recieve X and one cell will get Y. As per our answer, non disjunction happened during meiosis II in the phone having X chromosome and due to non disjunction the two sister chromatids of X don't separate . Because of this cell will contain two X chromosomes though the other resultant cell will have none.
Non-disjunction of the X- chromosome during meiosis II can cause one of the four gametes to have two X chromosomes and one having neither an X nor a Y chromosome.
Spermatogenesis:
It is the process of production of sperm from germ cells in males. During meiosis I the non-sister chromatids of the homologous chromosome exchange their genetic material to produce 2 diploid cells with a unique genetic combination.
- In Meiosis II, the non-sister chromatids separate to form 4 haploid cells with different genetic combinations.
- In Non-disjunction, one of the non-sister chromatids do not separate. This results in 2 normal cells, 1 cell with an extra chromosome, and other lakes one chromosome.
Therefore, Non-disjunction of the X- chromosome during meiosis II can cause one of the four gametes to have two X chromosomes and one having neither an X nor a Y chromosome.
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