Answer:
Explanation:
When two charge is brought from infinity to a distance d apart each other it take W amount of work.
i.e. Work done is equals to change in Potential Energy of the system
[tex]W=\frac{kq\cdot q}{d^2}[/tex]
When three Charges are moved from infinity to a distance apart from each other
Work required=Potential Energy of the three charge system
[tex]W'=\frac{kq^2}{d}+\frac{kq^2}{d}+\frac{kq^2}{d}[/tex]
[tex]W'=3\times \frac{kq^2}{d}[/tex]
[tex]W'=3W[/tex]
Therefore work required will be three times of original work