A very long straight wire has charge per unit length 1.44×10-10C/m.

question:

At what distance from the wire is the magnitude of the electric field equal to 2.45 N/C ?
Use 8.85×10−12C2/(N*m2) for the permittivity of free space, and use π=3.14 .

Respuesta :

Answer:

Distance of the point where electric filed is 2.45 N/C is 1.06 m            

Explanation:

We have given charge per unit length, that is liner charge density [tex]\lambda =1.44\times 10^{-10}C/m[/tex]

Electric field E = 2.45 N/C

We have to find the distance at which electric field is 2.45 N/C

We know that electric field due to linear charge is equal to

[tex]E=\frac{\lambda }{2\pi \epsilon _0r}[/tex], here [tex]\lambda[/tex] is linear charge density and r is distance of the point where we have to find the electric field

So [tex]2.45=\frac{1.44\times 10^{-10} }{2\times 3.14\times 8.85\times 10^{-12}\times r}[/tex]

r = 1.06 m

So distance of the point where electric filed is 2.45 N/C is 1.06 m