Answer:
Radius in mm will be 4.425 mm
Explanation:
We have given given escape speed of earth is equal to speed of the light as [tex]v=3\times 10^8m/sec[/tex]
Gravitational constant [tex]G=6.67\times 10^{-11}Nm^2/kg^2[/tex]
Mass of the earth [tex]M=5.972\times 10^{24}kg[/tex]
We have to find the radius of the earth
We know that escape speed is [tex]v=\sqrt{\frac{GM}{R}}[/tex]
So [tex]3\times 10^8=\sqrt{\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{R}}[/tex]
Squaring both side[tex]9\times 10^{16}={\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{R}}[/tex]
[tex]R=4.425\times 10^{-3}m=4.425mm[/tex]
So radius in mm will be 4.425 mm
