An unknown charge sits on a conducting solid sphere of radius 13 cm. If the electric field 21 cm from the center of the sphere has magnitude 3.7 × 103 N/C and is directed radially inward, what is the net charge on the sphere?

Respuesta :

Answer:

Charge on the sphere will be equal to [tex]q=1.81\times 10^{-8}C[/tex]    

Explanation:

We have given radius of the sphere a = 13 cm

And electric filed 21 cm from the center is [tex]3.7\times 10^3N/C[/tex]

So distance from the center r = 21 cm

We have to find the charge on the sphere

As [tex]r> a[/tex]

So according to Gauss law electric field is equal to

[tex]E=\frac{1}{4\pi \epsilon _0}\frac{q}{r^2}[/tex]

So [tex]3.7\times 10^3=9\times 10^9\times \frac{q}{0.21^2}[/tex]

[tex]q=1.81\times 10^{-8}C[/tex]

So charge on the sphere will be equal to [tex]q=1.81\times 10^{-8}C[/tex]