Respuesta :
Answer:
Force on the singly charged ion will be [tex]12.6\times 10^{-13}N[/tex]
Explanation:
We have given electric field E = 8 MN/C
So electric field in N/C will be [tex]E=8MN/C=8\times 10^6N/C[/tex]
It is given that ion so charge on ion will be equal to [tex]e=1.6\times 10^{-19}C[/tex]
We have to find the electric force on the ion
Electric force is equal to [tex]F=qE[/tex], here q is charge and E is electric field
So force on the charge will be equal to [tex]F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N[/tex]
So force on the singly charged ion will be [tex]12.6\times 10^{-13}N[/tex]
The force on a single charged ion is [tex]12.8\times 10^{-13}\;\rm N[/tex].
How do you calculate the Force?
Given that the electric field inside a cell membrane is 8.0 MN/C.
The force on a single charged ion is given below.
[tex]F = qE[/tex]
Where F is the force on an ion, E is the electric field and q is the charge of the ion.
Let us consider that the charged ion is an electron, then the charge q is the charge on the electron. Hence the force at the ion can be calculated by substituting the values on the above equation.
[tex]F = 1.6 \times 10^{-19} \times 8.0 \times 10^6[/tex]
[tex]F = 12.8\times 10^{-13}\;\rm N[/tex]
Thus, the force on a single charged ion is [tex]12.8\times 10^{-13}\;\rm N[/tex].
To know more about the force, follow the link given below.
https://brainly.com/question/2598777.
