Answer:
a) [tex]0.316[/tex]
b) [tex]0.105[/tex]
c) [tex]0.035[/tex]
d) [tex]0.0117[/tex]
e) [tex]0.0039[/tex]
Explanation:
When two heterozygous plants with genotype Bb are crossed, following offspring are produced
Bb * Bb
BB, Bb, Bb, bb
so the probability of blue offspring is [tex]\frac{3}{4}[/tex] and the probability of white offspring is [tex]\frac{1}{4}[/tex]
a) Probability of all 4 peas as blue
[tex]\frac{3}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{81}{256} \\= 0.316[/tex]
b) Probability of 3 blue and 1 white
[tex]\frac{3}{4} * \frac{3}{4}* \frac{3}{4}* \frac{1}{4}\\= \frac{27}{256} \\= 0.105[/tex]
c) Probability of 2 blue and 2 white
[tex]\frac{3}{4} * \frac{3}{4}* \frac{1}{4}*\frac{1}{4}\\= 0.035[/tex]
d) Probability of 1 blue and 3 white
[tex]\frac{3}{4} * \frac{1}{4} * \frac{1}{4}* \frac{1}{4}\\= \frac{3}{256} \\= 0.0117[/tex]
e) Probability of all white
[tex]\frac{1}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{1}{256} \\= 0.0039[/tex]
