Answer:
39.9 V
Explanation:
Given that
Capacitor are indentical that is why the value of C will be same for both the capacitor.
We know that energy stored in the capacitor is given as
[tex]E=\dfrac{1}{2}CV^2[/tex]
V=Voltage
C=Capacitance
For A :
E₁= 2 x 10⁻³ J
Voltage = V₁
For B :
E₂=1.8 x 10⁻⁴ J
V₂ = 12 V
[tex]E_1=\dfrac{1}{2}\times CV_1^2[/tex]
[tex]2\times 10^{-3}\times 2=CV_1^2[/tex]
[tex]E_2=\dfrac{1}{2}\times CV_2^2[/tex]
[tex]1.8\times 10^{-4}\times 2=C\times 12^2[/tex]
Now by using above two equation
[tex]\dfrac{2\times 10^{-3}\times 2}{1.8\times 10^{-4}\times 2}=\dfrac{CV_1^2}{C\times 12^2}\\11.11\times 12^2=V_1^2\\V_1=\sqrt{1599.84}\\V_1=39.9\ V[/tex]
Therefore the voltage on capacitor A will be 39.9 V
