Identify the structure of a compound of molecular formula C4H8O2 that gives the following 1H NMR data: 0.95 (triplet, 3 H), 1.65 (multiplet, 2 H), 2.30 (triplet, 2 H), and 11.8 (singlet 1 H) ppm.

Respuesta :

Answer:

It's Butanoic acid

CH3-CH2-CH2-COOH

Explanation:

-CH3 has the 0.95 triplet band

-CH2 has the 1.65 multiplet band having five proton around it

-CH2 has the 2.30 triplet band because it is attached to the carbon bearing the carboxylic group

While the last singlet H at 11.8 is that of the -COOH.