Trained dolphins are capable of a vertical leap of 7.0 m straight up from the surface of the water - an impressive feat. Suppose you could train a dolphin to launch itself out of the water at this same speed but at an angle. What maximum horizontal range could the dolphin achieve?

Respuesta :

Answer:14 m

Explanation:

Given

Vertical jump make by the dolphin is given by [tex]h=7\ m[/tex]

Suppose the dolphin jump with an initial velocity of [tex]u[/tex]

so u is given by [tex]u^2=2\cdot g\cdot h[/tex]

If dolphin launches at an angle [tex]\theta [/tex] then maximum horizontal range is given by

assuming the of Dolphin to be Projectile so range is given by

[tex]R=\frac{u^2\sin 2\theta }{g}[/tex]

substitute the value of [tex]u^2[/tex]

[tex]R=\frac{2\times 9.8\times 7\sin 2\theta }{9.8}[/tex]

[tex]R=2h\sin 2\theta [/tex]

Range will be maximum for [tex]\theta =45^{\circ}[/tex]

thus [tex]R_{max}=2\times 7\times 1=14\ m[/tex]