Respuesta :
Explanation:
As the cross-section of wire is a square so, it means that height of the wire is same length as the width.
Now, we will convert both height and width into centimeters as follows.
h = w
= [tex]\frac{22 nm \times 10^{-9} m}{1 nm} \times \frac{1 cm}{1 m}[/tex]
= [tex]2.2 \times 10^{-6} cm[/tex]
Length of wire will also be converted into centimeters as follows.
l = [tex]\frac{1 mm \times 1 m}{1000 mm} \times \frac{100 cm}{1 m}[/tex]
= 0.1 cm
Now, we will calculate the volume of the wire as follows.
V = [tex]l \times b \times h[/tex]
= [tex]0.1 cm \times 2.2 \times 10^{-6} cm \times 2.2 \times 10^{-6} cm[/tex]
= [tex]4.84 \times 10^{-13} cm^{3}[/tex]
Now, we will convert moles of copper into atoms of copper as follows.
[tex]\frac{4.84 \times 10^{-13} cm^{3} \times 8.96 g Cu \times 1 mol Cu \times 6.022 \times 10^{23}}{1 cm^{3} Cu \times 63.546 g Cu \times 1 mol Cu}[/tex]
= [tex]4 \times 10^{10} atom Cu[/tex]
Thus, we can conclude that there will be [tex]4 \times 10^{10} \text{atom Cu}[/tex] would be in a length of such an interconnect, assuming a square cross section.
