Answer:
Frequency of heterozygous animals with agouti fur is [tex]42[/tex] %
Explanation:
As per the Hardy Weinberg's equation -
[tex]q^2[/tex] represents the frequency of population with phenotype expressed by homozygous recessive genotype
[tex]p^ 2[/tex] represents the frequency of population with phenotype expressed by homozygous dominant genotype
and [tex]2pq[/tex] represents the frequency of population with phenotype expressed by homozygous recessive genotype
Given -
[tex]q^2 = 0.49\\q = 0.7[/tex]
As per first principle of Hardy Weinberg's equilibrium
[tex]p + q = 1[/tex]
Substituting the value of q in above equation, we get -
[tex]p = 1- 0.7 \\p = 0.3[/tex]
As per second principle of Hardy Weinberg's equilibrium
[tex]p^2 + q^2 + 2pq = 1\\[/tex]
Substituting the given values in above equation, we get -
[tex]0.09 + 0.49 + 2pq = 1\\2pq = 1 - 0.58 \\2pq = 0.42[/tex]
Frequency of heterozygous animals with agouti fur is [tex]42[/tex] %