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Three arrows are shot horizontally. They have left the bow and are traveling parallel to the ground. Air resistance is negligible. Rank in order, from largest to smallest, the magnitudes of the horizontal forces F1, F2, and F3 acting on the arrows. Some may be equal. State your reasoning.

Arrow 1: is 80g @ 10 m/s
Arrow 2: is 80g @ 9 m/s
Arrow 3: is 90g @ 9 m/s

Respuesta :

Answer:

F₁ = F₂ = F₃ = 0 N

Explanation:

given,

Arrow 1 mass = 80 g   speed = 10 m/s

Arrow 2 mass = 80 g   speed = 9 m/s

Arrow 3 mass = 90 g   speed = 9 m/s

Horizontal Force:- F₁ , F₂ and F₃

There is no air resistance.

If Air resistance is zero then the horizontal acceleration of the arrow also equal to zero.

We know,

According to newton's second law

        F = m a

If Acceleration is equal to zero

Then Force is also equal to zero.

Hence, F₁ = F₂ = F₃ = 0 N

onyebuchinnaji

The third arrow has the greatest force, followed by the first arrow and the least is the second arrow. (F₃ > F₁ > F₂)

The given parameters;

  • Arrow 1, mass = 80 g, velocity, v = 10 m/s
  • Arrow 2, mass = 80 g, velocity, v = 9 m/s
  • Arrow 3, mass = 90 g, velocity, v = 9 m/s

The magnitude of the horizontal force on each arrow is determined by applying Newton's second law of motion;

[tex]F = ma = \frac{mv}{t}[/tex]

The magnitude of force on an object is directly proportional to the velocity but inversely proportional to time action.

For example:

  • Let the common time for their motion = 2 s

The magnitude of the horizontal force on each arrow is calculated as;

[tex]F_1 = \frac{0.08 \times 10}{2} = 0.4 \ N[/tex]

[tex]F_2 = \frac{0.08 \times 9}{2} = 0.36 \ N\\\\F_3 = \frac{0.09 \times 9}{2} = 0.41 \ N[/tex]

Thus, we can conclude that the third arrow has the greatest force, followed by the first arrow and the least is the second arrow. (F₃ > F₁ > F₂)

Learn more here: https://brainly.com/question/19887955

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