a) Magnitude of the change in momentum: 24,200 kg m/S
b) Magnitude of the change in kinetic energy: [tex]1.33\cdot 10^5 J[/tex]
Explanation:
a)
The change in momentum of an object when its velocity changes is given by
[tex]\Delta p = m(v-u)[/tex]
where
m is the mass of the object
u is its initial velocity
v is its final velocity
For each of the two cars in this problem, we have:
m = 2200 kg (mass)
v = 0 (final velocity, since they come to a stop)
u = 11 m/s (initial velocity)
Therefore, the change in momentum is
[tex]\Delta p =(2200)(0-11)=-24200 kg m/s[/tex]
So, the magnitude of the change in momentum is 24,200 kg m/s.
b)
The kinetic energy of an object is the energy possessed by the object due to its motion, and it is given by
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is its speed
For each of the cars in this problem, we have:
m = 2200 kg
Initial speed is v = 11 m/s, so initial kinetic energy is
[tex]K_i = \frac{1}{2}(2200)(11)^2=1.33\cdot 10^5 J[/tex]
And final speed is v = 0, so final kinetic energy is
[tex]K_f=\frac{1}{2}(2200)(0)^2=0[/tex]
Therefore, the magnitude of the change in kinetic energy of each cart is [tex]1.33\cdot 10^5 J[/tex].
Learn more about momentum:
brainly.com/question/7973509
brainly.com/question/6573742
brainly.com/question/2370982
brainly.com/question/9484203
About kinetic energy:
brainly.com/question/6536722
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