Respuesta :
Answer:
The voltage is 2.114 V.
Explanation:
Given that,
Mass of both weights = 225 gm
Transducer sensitivity = 0.5 V/N
The first mass is located 20∘ north of east, the second mass is located 20∘ south of east,
We need to calculate the net equivalent force
Using formula of force
[tex]F_{3}=m_{1}g\cos\theta+m_{2}g\cos\theta[/tex]
[tex]F_{3}=2mg\cos\theta[/tex]
Put the value into the formula
[tex]F_{3}=2\times0.225\times10\cos20^{\circ}[/tex]
[tex]F_{3}=4.228\ N[/tex]
We need to calculate the voltage
Using formula of voltage
[tex]Voltage =sensitivity\times F_{3}[/tex]
Put the value into the formula
[tex]Voltage=0.5\times4.228[/tex]
[tex]Voltage =2.114\ V[/tex]
Hence, The voltage is 2.114 V.
The expected voltage is 2.07 V.
Given that,
Mass of both weights = m₁ = m₂ = 225 gm
Transducer sensitivity = 0.5 V/N
The first mass is located at θ₁ = 20° north of east, the second mass is located θ₂ = 20° south of east,
The net equivalent force F:
[tex]F=m_1gcos\theta_1+m_2gcos\theta_2\\\\F=2mgcos\theta\\\\F=2times 0.225\times 9.8\times cos20\\\\F=4.14N[/tex]
Now, the equivalent voltage V is:
V = sensitivity × F
[tex]V=0.5\times 4.14V\\\\V=2.07Volts[/tex]will be measured by the transducer.
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