Respuesta :
Answer:
16.566g
Explanation:
The 0.223M barium bromide means there are 0.223 moles of barium bromide is 1000ml of barium bromide solution.
Now, we firstly need to know the number of moles in 250ml
And that is = (0.223 * 250)/1000 = 0.05575 mole
Now we need to know the amount in g of barium bromide to add.
From the relation : mass = number of moles * molar mass.
The molar mass of barium bromide is 297.14g/mol
mass = 297.14 * 0.05575 = 16.566g
Answer:
16.558 g of BaBr2.
Explanation:
Molar concentration, M of a substance is defined as the number of moles of the solute in a unit volume of the solution.
M = 0.223 mol/l
Volume = 250 mL
Converting from mL to l,
250 ml = 0.25 l.
Number of moles = M * V
= 0.223 * 0.25
= 0.05575 mol.
Molar mass of BaBr2 = 137 + (80*2)
= 297 g/mol
Mass = molar mass * number of moles
= 297 * 0.05575
= 16.558 g of BaBr2.
