Answer:
The minimum amount of such material that should be shipped is 63.9 mg≅ 64 mg.
Explanation:
Given Data:
Half life=1.8 hours
Formula:
Half life=0.693/k
Where:
k is rate constant
k=0.693/1.8
k=0.385 hr^-1
Formula to find initial concentration:
[tex]ln\frac{A}{A_o}=-kt[/tex]
Where:
A is final concentration
A_o is initial concentration
t is time
Taking exponential on both sides:
[tex]\frac{A}{A_o}=e^{-kt}\\ A_o=\frac{A}{e^{-kt}}\\ A_o=63.9 mg[/tex]
The minimum amount of such material that should be shipped is 63.9 mg≅ 64 mg.
