PLEASE HELPPP!!!!!! Write an equation of the line passing through point P that is perpendicular to the given line.

P(−1,−2), y=−4x+13

Respuesta :

Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13

because of (d)⊥(d1) --> a.(-4)=-1 --> a=[tex]\frac{1}{4}[/tex]

(d): y=[tex]\frac{1}{4}x[/tex]+b. (d) pass through  P(-1;-2) so we have

-2=(1/4).(-1)+b ---> b=[tex]\frac{-7}{4}[/tex]

(d) y= [tex]\frac{1}{4}x+ \frac{-7}{4}[/tex]