Respuesta :

The specific heat, c is 0.75 J/g°C

Explanation:

Heat or Energy, Q = 1500J

Mass, m = 50g

T1 =  0°C

T2 = 40°C

Specific Heat, c = ?

We know,

Q = mcΔT

Q = mc(T2-T1)

1500 = 50 X c X (40-0)

1500 = 50 X c X 40

c = 1500/ 2000

c = 0.75 J/g°C

Therefore, the specific heat, c is 0.75 J/g°C