Respuesta :
Answer:
Explanation:
Given
combined mass of cab and occupant is [tex]M=1820\ kg[/tex]
acceleration of coin w.r.t cab is [tex]a_{co,c}=8.50\ m/s^2(downward)[/tex]
we can write
[tex]a_{co,c}+a_{c,g}=a_{co,g}[/tex]
where [tex]a_{co,c}[/tex]=acceleration of coin w.r.t cab
[tex]a_{c,g}[/tex]=acceleration of cab w.r.t ground
[tex]a_{co,g}[/tex]=acceleration of coin w.r.t ground
thus [tex]-8.5+a_{c,g}=-9.8[/tex]
[tex]a_{c,g}=-9.8+8.5[/tex]
[tex]a_{c,g}=-1.3\ m/s^2[/tex] i.e. elevator is moving downward with an acceleration of [tex]1.3 m/s^2[/tex]
Therefore
[tex]T-Mg=Ma_{c,g}[/tex]
[tex]T=M(g+a)[/tex]
[tex]T=1820\cdot (9.8-1.3)[/tex]
[tex]T=1820\times 8.5[/tex]
[tex]T=15,470\ N[/tex]
[tex]T=15.47\ kN[/tex]
