Answer:
1) 236 s
2) 91%
3) no
Explanation:
solution:
The new time required to run FP operations is
0.8 x 70 s = 56 s
So, the new time required to run the program is
250 — (70 — 56) = 236 s (because we reduced the time of execution by 70 — 56 = 14 seconds).
The new total time of execution is
0.8 x 250 = 200 s
If we assume that we changed only the time needed to execute INT operations, the new time needed to execute INT operations is
200 — 70 — 85 — 40 = 5 s
Since the old time was 250 — 70 — 85 — 40 = 55 seconds, and
5/55=0.09
this is the decrease of a whooping 91%!
Let's assume that we completely avoid using branch operations. Then the time of execution is
55 + 70 + 85 = 205
This is the decrease of 18%, since 205/250 = 0.82 This means that we cannot decrease the total time by 20% by just decreasing the time of branch operations.
in this exercise we have to use the knowledge of computers to calculate the time that can be reduced, in this way:
A) 236 s
B) 91%
C) no
Knowing that to calculate the time of operations:
[tex]0.8 * 70 s = 56 s[/tex]
[tex]250 -(70 - 56) = 236 s[/tex]
The new total time of execution will be:
[tex]0.8 * 250 = 200 s \\200 - 70 - 85 - 40 = 5 s\\250 - 70 - 85 - 40 = 55\\5/55=0.091=91\%[/tex]
Then the running time is given by:
[tex]55 + 70 + 85 = 205\\ 205/250 = 0.82[/tex]
See more about computers at brainly.com/question/950632
