The magnitude of WX is [tex]\sqrt{29}[/tex] ⇒ c
Step-by-step explanation:
The magnitude of XY (its length) where,
is IXYI = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}[/tex]
∵ W = (-2 , 8 , -3)
∵ X = (1 , 4 , -1)
- To find the magnitude of WX use the formula above
∴ [tex]x_{1}[/tex] = -2 and [tex]x_{2}[/tex] = 1
∴ [tex]y_{1}[/tex] = 8 and [tex]y_{2}[/tex] = 4
∴ [tex]z_{1}[/tex] = -3 and [tex]z_{2][/tex] = -1
- Substitute these values in the rule above
∵ IWXI = [tex]\sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}[/tex]
∴ IWXI = [tex]\sqrt{29}[/tex]
The magnitude of WX is [tex]\sqrt{29}[/tex]
Learn more:
You can learn more about the position of an object in brainly.com/question/10940255
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