HELP ASAP!!

A potential difference of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 meters per second perpendicular to a uniform magnetic field. What is the strength of the magnetic field?

A

7.2 T


B

13 T


C

20. T


D

180 T

Respuesta :

C. 20 T

The strength of the magnetic field is equal to 20 Tesla.

Explanation:

Given:

Induced potential difference = V = 12 V

Length of wire = L = 0.20 m

Speed of the moving wire = V = 3.0 m/s

Magnetic field strength = B = ?

A conductor, placed in a uniform magnetic field; when moved at a constant speed with respect to the field, leads to a changing magnetic flux, generating an electromotive force (EMF). Using, Faraday's law of magnetic induction, a moving conductor's induced EMF in terms of the magnetic field strength is given by :

[tex]E = L\times V\times B[/tex]......................(1)

where

E = Induced potential difference (EMF)

L = Length of the conductor

V = Speed of the conductor moved with respect to the magnetic field

B = Strength of uniform magnetic field

Rewriting equation (1) for B, we get

[tex]B = \frac{E}{L\times V} = \frac{12}{0.2\times 3} = \frac{12}{0.6} = 20\ T[/tex]

The strength of magnetic field is equal to 20 Tesla.