A potentialiterence of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 meters per second perpendicular to a uniform magnetic field. What is the strength of the magnetic field?
A 7.27 T
B 137 T
c 20. T
D 180 T

For a conductive wire moving perpendicular to a magnetic field, the electromotive force (voltage) induced in the wire due to electromagnetic induction is given by

[tex]\epsilon=BvL[/tex]

where

B is the strength of the magnetic field

v is the speed of the wire

L is the length of the wire

For the wire in this problem, we have:

[tex]\epsilon=12 V[/tex] (induced emf)

L = 0.20 m (length of the wire)

v = 3.0 m/s (speed)

Solving for B, we find the strength of the magnetic field:

[tex]B=\frac{\epsilon}{vL}=\frac{12}{(0.20)(3.0)}=20 T[/tex]

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A potentialiterence of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 meters per second perpendicular to a uniform magnetic field. What is the strength of the magnetic field? A 7.27 T B 137 T c 20. T D 180 T

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A potentialiterence of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 meters per second perpendicular to a uniform magnetic field. What is the strength of the magnetic field?
A 7.27 T
B 137 T
c 20. T
D 180 T