Answer: The molecular formula of the compound is [tex]C_9H_{18}[/tex]
Explanation:
We are given:
Empirical formula of the compound = [tex]CH_2[/tex]
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
[tex]n=\frac{\text{Molecular mass}}{\text{Empirical mass}}[/tex]
We are given:
Mass of molecular formula = 126 g/mol
Mass of empirical formula = [tex]12+(2\times 1)]=14g/mol[/tex]
Putting values in above equation, we get:
[tex]n=\frac{126g/mol}{14g/mol}=9[/tex]
Multiplying this valency by the subscript of every element of empirical formula, we get:
[tex]C_{(9\times 1)}H_{(9\times 2)}=C_9H_{18}[/tex]
Hence, the molecular formula of the compound is [tex]C_9H_{18}[/tex]
