Answer:29.8 cm/s
Explanation:
Given
mass of marble A is [tex]m_a=20.6\ gm[/tex]
Initial velocity of marble A is [tex]u_a=59.6\ cm/s[/tex]
mass of marble B is [tex]m_b=10.3\ gm[/tex]
Initial velocity of marble B [tex]u_b=14.9\ cm/s[/tex]
After collision marble B moves with velocity of [tex]v_b=74.5\ cm/s[/tex]
Conserving momentum
[tex]m_au_a+m_bu_b=m_av_a+m_bv_b[/tex]
[tex]20.6\times 59.6+10.3\times 14.9=20.6\times v_a+10.3\times 74.5[/tex]
[tex]v_a=\frac{20.6\times 59.6-10.3(74.5-14.9)}{20.6}[/tex]
[tex]v_a=29.8\ cm/s[/tex]
