Answer:
1.29 mL.
Explanation:
Equation of the reaction:
H2SO4(aq) + Ba(NO3)2(aq) --> BaSO4 + 2HNO3(aq)
Mass of Ba(NO3)3 = wt% * mass of the solid
= 23.2 x 4.35 / 100
= 1.01 g
Number of moles of Ba(NO3)2 = mass/molar mass
Molar mass of Ba(NO3)2 = 137 + (14 + (16 * 3))*2
= 261 g/mol
= 1.01 / 261
= 0.00387
By stoichiometry, since 1 mole of Ba(NO3)2 reacted with 1 mole of H2SO4. Therefore, number of moles of H2SO4 = 0.00387 moles.
Volume = number of moles/molar concentration
= 0.00387/3
= 0.00129 L
= 1.29 mL.
