Answer: 0.4M
Explanation:
This would be much easier if we first analized what was given from the question. This is illustrated below:
C1 = 2M
V1 = 25mL
C2 =?
V2 = 125mL
C1V1 = C2V2
2x25= C2 x 125
Divide both side by 125, we have:
C2 = (2x25) /125
C2 = 0.4M
Therefore, the molarity of potassium bromide formed will be 0.4M