Answer:
D = 527.31 Km
Explanation:
given,
angle of ship, θ = 23.5° N of W
distance travel in the direction = 575 Km
Distance of ship in west from harbor = ?
now,
Distance of the ship in the west direction
D = d cos θ
d = 575 Km
θ = 23.5°
inserting all the values
D = 575 x cos 23.5°
D = 575 x 0.91706
D = 527.31 Km
Hence, the distance travel by the ship in west from harbor is equal to D = 527.31 Km
The distance traveled by the ship will be "527.31 Km".
According to the question,
Ship's angle, θ = 23.5° (North to West)
Distance travelled = 575 Km
We know relation, we get
→ D = dCosθ
By substituting the values, we get
= 575 × Cos 23.5°
= 575 × 0.91706
= 527.31 Km
Thus the above answer is correct.
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