Mrs lin is sewing costumes for her grandchildren.She is making three lion costumes one zebra costume and two bear. Costumes fabric costs $ 7.49 per yard how much fabric does Mrs lin need

The complete exercise is: "Mrs. Lin is sewing costumes for her grandchildren. She is making three lion costumes, one zebra costume, and two bear costumes. Fabric costs $7.49 per yard. How much fabric does Mrs. Lin need?

[tex]Bear= 2 \frac{1}{4}\ yards \\\\Lion= 1 \frac{2}{3}\ yards\\\\Zebra= 2 \frac{5}{8} yards[/tex] "

You need to find the total amount of fabric (in yards) that Mrs. Lin needs to make three lion costumes, one zebra costume, and two bear costumes.

Let be:

"l" the amount of fabric (in yards) that Mrs. Lin needs to make three lion costumes.
"z" the amount of fabric (in yards) that Mrs. Lin needs to make one zebra costume.
"b" the amount of fabric (in yards) that Mrs. Lin needs to make two bear costumes.

First, you can convert the mixed numbers given in the exercise to decimal numbers:

- Divide the numerator by the denominator.

- Add the quotient to the Whole number part.

Then:

[tex]Bear= (2+0.25)\ yards=2.25\ yards \\\\Lion=(1+0.666)\ yards=1.666\ yards\\\\Zebra=(2+0.625)=2.625\ yards[/tex]

Therefore, you can determine that "l", "z" and "b" are:

[tex]l=3(1.666\ yards)=4.998\ yards\\\\z=2.625\ yards\\\\b=2(2.25\ yards)=4.5\ yards[/tex]

Finally, in order to find the total amount of frabric (in yards) that she needs, you need to add "l", "z" and "b". Then, you get:

[tex]Total=l+z+b\\\\Total=4.998\ yards+2.625\ yards+4.5\ yards\\\\Total=12.123\ yards[/tex]