Respuesta :

Answer:

The temperature must be 337.42 K.

Explanation:

At constant pressure and number of moles, using Charles's law  

[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]

Given ,  

At STP,

T₁ = 273.15 K

V₁ = 1700 mL

V₂ = 2100 mL

T₂ = ?

Using above equation as:

[tex]\frac{1700}{273.15}=\frac{2100}{T_2}[/tex]

[tex]T_2=\frac{2100\cdot \:273.15}{1700}\ K[/tex]

The temperature must be 337.42 K.