Answer : The molality of solution is, 0.866 mole/kg
Explanation :
The relation between the molarity, molality and the density of the solution is,
[tex]d=M[\frac{1}{m}+\frac{M_b}{1000}][/tex]
where,
d = density of solution = 1.0052 g/ml
m = molality of solution = ?
M = molarity of solution = 0.828 M = 0.828 mol/L
[tex]M_b[/tex] = molar mass of solute (acetic acid) = 60.05 g/mole
Now put all the given values in the above formula, we get the molality of the solution.
[tex]1.0052g/ml=0.828mol/L\times [\frac{1}{m}+\frac{60.05g/mole}{1000}][/tex]
[tex]m=0.866mol/kg[/tex]
Therefore, the molality of solution is, 0.866 mole/kg
